(x^(1/5)+25x)/x

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Solution for (x^(1/5)+25x)/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(25*x+x^(1/5))/x = 0

25*x+x^(1/5) = 0

x^(1/5)*(25*x^(4/5)+1) = 0

25*x^(4/5) = -1 // : 25

x^(4/5) = -1/25

( -1/25 < 0 i 4/5 in (0:1) ) => x naleu017Cy do O

x^(1/5) = 0

(x^(1/5))/x = 0

1*x^(1/5) = 0 // : 1

x^(1/5) = 0

x = 0

x in { 0} 

x belongs to the empty set

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